x^2+16x+18=0

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Solution for x^2+16x+18=0 equation:


Simplifying
x2 + 16x + 18 = 0

Reorder the terms:
18 + 16x + x2 = 0

Solving
18 + 16x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-18' to each side of the equation.
18 + 16x + -18 + x2 = 0 + -18

Reorder the terms:
18 + -18 + 16x + x2 = 0 + -18

Combine like terms: 18 + -18 = 0
0 + 16x + x2 = 0 + -18
16x + x2 = 0 + -18

Combine like terms: 0 + -18 = -18
16x + x2 = -18

The x term is 16x.  Take half its coefficient (8).
Square it (64) and add it to both sides.

Add '64' to each side of the equation.
16x + 64 + x2 = -18 + 64

Reorder the terms:
64 + 16x + x2 = -18 + 64

Combine like terms: -18 + 64 = 46
64 + 16x + x2 = 46

Factor a perfect square on the left side:
(x + 8)(x + 8) = 46

Calculate the square root of the right side: 6.782329983

Break this problem into two subproblems by setting 
(x + 8) equal to 6.782329983 and -6.782329983.

Subproblem 1

x + 8 = 6.782329983 Simplifying x + 8 = 6.782329983 Reorder the terms: 8 + x = 6.782329983 Solving 8 + x = 6.782329983 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = 6.782329983 + -8 Combine like terms: 8 + -8 = 0 0 + x = 6.782329983 + -8 x = 6.782329983 + -8 Combine like terms: 6.782329983 + -8 = -1.217670017 x = -1.217670017 Simplifying x = -1.217670017

Subproblem 2

x + 8 = -6.782329983 Simplifying x + 8 = -6.782329983 Reorder the terms: 8 + x = -6.782329983 Solving 8 + x = -6.782329983 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + x = -6.782329983 + -8 Combine like terms: 8 + -8 = 0 0 + x = -6.782329983 + -8 x = -6.782329983 + -8 Combine like terms: -6.782329983 + -8 = -14.782329983 x = -14.782329983 Simplifying x = -14.782329983

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-1.217670017, -14.782329983}

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